You need to 'cook' the WAR file before deploying it to Tomcat using
wsdeploy.
You will also need to 'update' the Tomcat XML parser. TC uses the standard
Xerces, JWSDP 1.4 relies on Sun's version of Xerces. As a minimum you will
need to copy %JWSDP_HOME%\jaxp\lib\endorsed to
%TOMCAT_HOME%\common\endorsed. You could also run the jwsdpontomcat script
that's in %JWSDP_HOME%\jwsdp-shared\bin specifying the TC directory, but
that changes more than just the endorsed parser,
Kevin Jones
http://kevinj.develop.com
> -----Original Message-----
> From: Merten Schumann [mailto:Merten.Schumann_at_asg.com]
> Sent: 03 August 2004 12:05
> To: users_at_jax-rpc.dev.java.net
> Subject: Re: Is Apache Axis required to deploy JAX-RPC application?.
>
> Hello,
>
> found this thread regarding Tomcat and JAX-RPC web service and have a
> question:
>
> I've created a raw web service .war (just my classes,
> jaxrpc-ri.xml and
> model.xml.gz) which is working when deployed to Sun App
> Server 8.0 and IMB WebSphere 6.0. I created the model with
> wscompile from Sun's J2EE
> 1.4 RI.
>
> Now I tried Tomcat (5.0.14). I copied the .war to
> <tomcat>\webapps. In the console, I saw
>
> org.apache.catalina.core.StandardHostDeployer install
> INFO: Installing web application at context path
> /HelloService_raw from URL file
> :D:/work/soap/jakarta-tomcat-5.0.14/webapps/HelloService_raw
>
> And nothing more, no error ...
>
> My jaxrpc-ri.xml looks like this
>
> <?xml version="1.0" encoding="UTF-8"?>
> <webServices
> xmlns="http://java.sun.com/xml/ns/jax-rpc/ri/dd"
> version="1.0"
> targetNamespaceBase="http://java.sun.com/xml/ns/jax-rpc/wsi/wsdl"
> typeNamespaceBase="http://java.sun.com/xml/ns/jax-rpc/wsi/types"
> urlPatternBase="/ws">
>
> <endpoint
> name="DefaultEndpoint"
> displayName="HelloService Example"
> description="HelloService Example endpoint"
> interface="de.rochade.srap.ws.HelloService"
> implementation="de.rochade.srap.ws.HelloServiceImpl"
> model="/web-inf/model.xml.gz"/>
>
> <endpointMapping
> endpointName="DefaultEndpoint"
> urlPattern="/rums"/>
> </webServices>
>
> I tried to access the WSDL of my service by
> localhost:8080/ws/rums?WSDL or
> localhost:8080/HelloService_raw?WSDL and all, but nothing
> happened. I think in the created folder
> <tomcat>/webapps/HelloService_war just the content from the
> .war has been extracted, no tie stuff or WSDL and all has
> been created (as it happens when I deploy the beast to other
> app servers). But I cannot use the cooked war (created with
> wsdeploy) since it's Sun specific.
>
> So, question is, can I deploy a raw JAX-RPC web service .war
> to Tomcat?
> Or do I need this "Tomcat for JWSDP_1_4"?
>
> Thank you!
> Merten
>
> > -----Original Message-----
> > From: Ramesh Babu Mandava [mailto:Ramesh.Mandava_at_Sun.COM]
> > Sent: Wednesday, June 30, 2004 1:54 AM
> > To: users_at_jax-rpc.dev.java.net
> > Subject: Re: Is Apache Axis required to deploy JAX-RPC application?.
> >
> > Hi Shaba:
> >
> > > Hi all,
> > >
> > > I have created a .war file by using wsdeploy tool(attached file).
> > >
> > > Now i wanna deploy it in a webserver.The target server is
> Tomcat4.1
> > > or 5.0.
> > >
> > > I have placed my .war file in webapps directory of Tomcat.and ran
> > > Tomcat.But i could'nt able to get the service from it.Tomcat says
> > > that the requested file is NOT AVAILEABLE.
> > >
> > > my time is precious.I have even made buisiness and data
> tier of my
> > > application,when i successfully test the JAX-RPC model,i can use
> > > JAX-RPC and i wanna use it.so anyone knowing plz help.
> > >
> > > I think it's a silly questien.A simple example.I am attaching the
> > > sunreg.war file with it.Plz check it out.
> >
> > JAX-RPC Standard Implementation is enough to develop, deploy and
> > invoke a JAX-RPC application.
> >
> > I extracted the attached target.war and find out that you
> don't have
> > endpointmapping for endpoint with name "SunRegService". Even though
> > you defined one endpointMapping element as part of
> "jaxrpc-ri.xml" (
> > which is stored as jaxrpc-ri-before.xml in the cooked war
> file), the
> > "endpointName" attribute value is set to "SunRegEndPoint"
> > which is not same as value "name" attribute of "endpoint" element.
> >
> > While using endpoint mapping you have to mention "endpointName"
> > value to be equal to the value of "name"
> > attribute of "endpoint" element.
> >
> > Anyway because there is no endpoint mapping defined for endpoint (
> > with name as SunRegService ) , JAXRPC SI used value of "name"
> > attribute of "endpoint" element as the "urlPattern". So the
> final URL
> > of the webservice would become
> >
> > http://<serverName>:<serverPort>/target/ws/SunRegService
> >
> > When I deployed your target.war in my Tomcat 5.0.19
> version which is
> > supported by JWSDP 1.4 ( available to download at [1] ), the
> > webservice is exposed at URL
> >
> > http://localhost:8080/target/ws/SunRegService
> >
> > Please look at the white papers [2] & [3] to understand more about
> > JAXRPC SI environment
> >
> > [1]
> > http://java.sun.com/webservices/containers/tomcat_for_JWSDP_1_4.html
> >
> > [2] https://jax-rpc.dev.java.net/whitepaper/1.1/index-part1.html
> > [3] https://jax-rpc.dev.java.net/whitepaper/1.1/index-part2.html
> >
> >
> >
> > Regards
> > -Ramesh
> >
> > >
> > > Thanks
> > > Shaba
> > >
> > >
> > >
> > > __________________________________
> > > Do you Yahoo!?
> > > Yahoo! Mail - Helps protect you from nasty viruses.
> > > http://promotions.yahoo.com/new_mail
> > >
> >
>
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