[Jersey] Re: Explicitly declare the root resource and provider classes - not working for provider class

From: Farrukh Najmi <>
Date: Thu, 01 Mar 2012 08:45:42 -0500

I was finally able to get my jersey rest end point to work inside an app
that was launched via JNLP / java webstart. It was painful because i had
to do the following...

    * Replace spring based bean config with hard-coded bean creation
    * Replace org.glassfish.grizzly.servlet.ServletHandler based Grizzly
      HttpServer creation with ResourceConfig based Grizzly HttpServer
    * Replace code in root resources that used
      HttpServletRequest/HttpServletResponse Context params
    * Upgrade from default Grizzly version for jersey 1.10 to grizzly
      2.1.10 to get fix for
      (thank Oleksiy Stashok for the quick fix!)
    * Replace package scaning for root resources and provider classes by
      extending DefaultResourceConfig and defining a getSingleton()
      override method to explicitly declared root resources and provider

All this was necessary because package scanning for root resources and
provider classes do not seem to work inside java webstart for reasons I
do not understand.

I have created to see if the root
issue could be addressed. Thanks to Glen Mazza and Oleksiy Stashok for
their kind help.

On 02/29/2012 09:02 AM, Farrukh Najmi wrote:
> I was using a org.glassfish.grizzly.servlet.ServletHandler to create
> the HttpServer as follows:
> import com.sun.jersey.api.container.grizzly2.GrizzlyServerFactory;
> import org.glassfish.grizzly.http.server.HttpServer;
> import org.glassfish.grizzly.http.server.ServerConfiguration;
> import org.glassfish.grizzly.http.server.StaticHttpHandler;
> import org.glassfish.grizzly.servlet.ServletHandler;
> ...
> URI uri = ...
> ServletHandler servletHandler = new ServletHandler();
> HttpServer server = GrizzlyServerFactory.createHttpServer(uri,
> servletHandler, false);
> So I tried the following to use jersey ContainerFactory to create my
> handler so it takes into account my ResourceConfig (so I can
> explicitly set root resource and provider classes so I can run my
> jersey server inside a webstart / jnlp launched app):
> ServletHandler servletHandler =
> ContainerFactory.createContainer(ServletHandler.class, resourceConfig);
> HttpServer server = GrizzlyServerFactory.createHttpServer(uri,
> servletHandler, false);
> The problem I get is:
> No container provider supports the type class
> org.glassfish.grizzly.servlet.ServletHandler
> com.sun.jersey.api.container.ContainerFactory.createContainer(
> com.sun.jersey.api.container.ContainerFactory.createContainer(
> I am on my 5th day trying to get an app with a jersey server endpoint
> that worked fine standalone to work in javawebstart environment.
> I feel I am close but at the end of my knowledge of jersey to get this
> seemingly simple problem solved:
> How to explicitly declare the root resource and provider classes when
> using a ServletHandler in creating the Grizzly server.
> Any other ideas from the jesrey dev team?
> On 02/28/2012 08:04 PM, Glen Mazza wrote:
>> Just more detective work, basically see what Jersey does
>> behind-the-scenes. Go to grepcode on "GrizzlyServerFactory" -- line
>> 75 in the I linked to below. You'll see what Jersey does:
>> I see an HttpHandler in that method, so I'll leave the rest to you as
>> an exercise. :)
>> Glen
>> On 02/28/2012 07:36 PM, Farrukh Najmi wrote:
>>> On 02/28/2012 01:22 PM, Glen Mazza wrote:
>>>> On 02/28/2012 01:04 PM, Farrukh Najmi wrote:
>>>>> BTW, when I set breakpoints inside my getClasses() and
>>>>> getSingletons() methods of my "class HubSubscriber extends
>>>>>" I find they are never called!
>>>> Did you remember to wire your Application subclass in like here:
>>>> (lines 72-75)? Also, I'd try a System.out.println() in those two
>>>> methods to confirm they're not being called -- it could be the
>>>> debugger is wrong for some reason.
>>> I did not do that! So that explains why the getClasses() and
>>> getSingletons() methods are not being called.
>>> Now here is my problem. I am using the following method
>>> <>
>>> to create my HttpServer. I need to specify an HttpHandler. So how do
>>> I pass it a ResourceConfig instance? I think there is a way to
>>> create an HttpHandler with a specified ResourceConfig but I do not
>>> know how to do that. Any advice?
>>> Thanks again for your kind help.

Farrukh Najmi