Passing the parameter is not the problem. I want to process that parameter 
URI the same way the jersey container does and get a resource object out 
of it.
I want to process all the rules except the last one for HTTP method and 
the creation of the representation. I think all the code to do this is 
already in the container,
just need to find out how to get to it...
Paul Sandoz <Paul.Sandoz_at_Sun.COM> 
Sent by: Paul.Sandoz_at_Sun.COM
02/08/2010 04:38 AM
Please respond to
users_at_jersey.dev.java.net
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Subject
Re: [Jersey] howto RESTfully relate resources?
Hi,
Do you want to pass a URI as the value of a query parameter?
For example:
  
http://foo/blah&uri=http://bar/ugh
You can do:
  @GET
  public XXX get(@QueryParam("uri") URI uri) { ... }
because URI contains a constructor that has a single string parameter.
Note that you need to make sure the client constructors the URI with the 
embedded URI correctly such that the embedded URI is correctly encoded, 
for example if the embedded URI has query parameters the approach 
characters need to be percent encoded.
Paul.
On Feb 5, 2010, at 9:00 PM, FSauer_at_dsthealthsolutions.com wrote:
Imagine a scenario where on a page a user needs to relate various 
resources together - in its simplest form a copy/paste scenario. 
The resource being pasted is identified with a URI. Now a request is made 
to the service containing that URI of the resource being 
related to the receving resource.... How do I translate that URI to the 
actual to be related resource? 
The jersey container already knows how to do this when it receives a 
request on that resource.... 
Do I get access to that part of  the container code so I can determine the 
resource identified by a URI received as data , 
for example as a @QueryParam? 
Thanks,
<mime-attachment.gif> 
Frank Sauer
Principal Architect
DST Health Solutions
2500 Corporate Drive
Birmingham, AL 35242 
(205)437-5204 (Office) (Direct) 
(205)568-4684 (Cell)
fsauer_at_dsthealthsolutions.com 
It is impossible to sharpen a pencil with a blunt axe. It is equally vain 
to try to do it with ten blunt axes instead -- Edsger W. Dijkstra
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