As I understand, since I did not specify substitution group correct xml
should be:
<base xsi:type="derivedType>...</base>
Let me know if my understanding of XSD/XML is wrong.
Thanks
--- Karen
Wolfgang Laun-2 wrote:
>
> What do you see that is wrong?
> -W
>
>
>
> On Mon, Jul 20, 2009 at 7:05 PM, Qzpmwo <qzpmwo_at_gmail.com> wrote:
>
>>
>> Hi,
>>
>> I'm having a problem with derived schema types and XML generated by JAXB.
>>
>> Basically I'm having a schema like:
>>
>> <xs:schema>
>>
>> <xs:complexType name="BaseType">
>> <xs:sequence>
>> </xs:sequence>
>> </xs:complexType>
>>
>> <xs:complexType name="DerivedType">
>> <xs:complexContent>
>> <xs:extension base="BaseType">
>> <xs:sequence>
>> </xs:sequence>
>> </xs:extension>
>> </xs:complexContent>
>> </xs:complexType>
>>
>> <xs:complexType name="ListType">
>> <xs:sequence>
>> <xs:element name="item" type="BaseType" minOccurs="0"
>> maxOccurs="unbounded" />
>> </xs:sequence>
>> </xs:complexType>
>>
>> <xs:element name="base" type="BaseType" />
>> <xs:element name="derived" type="DerivedType" />
>> <xs:element name="list" type="ListType" />
>>
>> </xs:schema>
>>
>> XJC is used to generate java classes from this schema.
>>
>> 1) @XmlSeeAlso pointing to DerivedType class and @XmlRootElement
>> annotations have been added to BaseType java class code
>> 2) @XmlRootElement has been added to DerivedType java class code
>> 3) @XmlRootElement has been added to ListType java class code
>>
>> Right xml is produced when I'm using ListType
>>
>> <list>
>> <base xsi:type="DerivedType">...</base>
>> ...
>> </list>
>>
>> But when I'm trying to get single object of the DerivedType, I see wrong
>> xml
>> (since I'm not using substitution group):
>>
>> <derived>...</derived>
>>
>> So question: Is there a way to force JAXB return correct xml?
>>
>> Thanks in advance
>> --- Karen
>> --
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>>
>>
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>
>
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Sent from the java.net - jaxb users mailing list archive at Nabble.com.