users@jaxb.java.net

Re: "unexpected character literal " Validation Exception

From: Sam Cheung <sylcheung_at_hotmail.com>
Date: Tue, 24 Feb 2004 00:22:34 +0000

Okay,
I display this data from debugger:
columnNumber = 393
lineNumber = 1
node = null
object = null
offset = -1
url = null

Is this good enough?
Thanks for your help.


>From: Kohsuke Kawaguchi <Kohsuke.Kawaguchi_at_Sun.COM>
>Reply-To: users_at_jaxb.dev.java.net
>To: users_at_jaxb.dev.java.net
>Subject: Re: "unexpected character literal " Validation Exception
>Date: Mon, 23 Feb 2004 15:17:30 -0800
>
>
> > u.setEventHandler(new MyDefaultValidationEventHandler());
> > Here is the Validation error (Notice the Location is EMPTY STRING):
> > DefaultValidationEventHandler: [ERROR]: unexpected character literal
> > Location:
>
>Could you use the following ValidationEventHandler and tell us what the
>output is?
>
> public boolean handleEvent( ValidationEvent event ) {
> System.out.println( event.getLocator() );
> return true;
> }
>
>
>regards,
>--
>Kohsuke Kawaguchi
>Sun Microsystems kohsuke.kawaguchi_at_sun.com
>
>
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