After i read some tutorials I fix the problem.
But trying to develop my server client system, i got another issue.
I made another method which has to retrieve an attachment from web
service. Because is not defined a specific MIME type which can be
binded to the Java object, I got this error:
SEVERE: caught throwable
com.sun.xml.messaging.saaj.SOAPExceptionImpl: Error during saving a
multipart message
.............................................
javax.activation.UnsupportedDataTypeException: no object DCH for MIME
type application/octet-stream.
.............................................
on the server site I have something like that:
public DataHandler getOctet(String Id){
return new DataHandler(new FileDataSourse("contextPath"));
}
Any Idea to solve this problem ?
thanks
On 7/19/05, Oancea Daniel <doancea_at_gmail.com> wrote:
> Thanks for your reply Anne
>
> i read much better the tutorial and i made a client. But, the I still
> have a problem.
> The client that I made have to sent an attachment to an web service ,
> and get an answer from them. The think is that I don't get anything
> from the server side.
>
> The system server - client is very simple.
>
> here is a part from WSDL file:
>
> <wsdl:operation name="sendOctet">
> <soap:operation soapAction="sendOctet"/>
> <wsdl:input>
> <mime:multipartRelated>
> <mime:part>
> <soap:body use="literal"/>
> </mime:part>
> <mime:part>
> <mime:content part="octet"
> type="application/octet-stream"/>
> </mime:part>
> </mime:multipartRelated>
> </wsdl:input>
> <wsdl:output>
> <soap:body use="literal"/>
> </wsdl:output>
> </wsdl:operation>
>
> the interface generated by the wscompile using -import -f:wsi options
> is look like:
>
> public interface AttachmentPortType extends java.rmi.Remote {
> public java.lang.String sendOctet(javax.activation.DataHandler
> octet) throws
> java.rmi.RemoteException;
>
> the implementation of interface:
>
> public class AttachmentPortTypeImpl implements AttachmentPortType{
>
> public String sendOctet(javax.activation.DataHandler octet) {
> return ("***Service received DataHandler of type: " +
> octet.getContentType());
> }
>
> and the client :
>
>
> public static void main(String[] args) {
> try {
> Stub proxy = proxy();
>
> AttachmentPortType req = (AttachmentPortType) proxy;
>
> FileDataSource file = new FileDataSource("e://lucru/IMSClient/conf/test.txt");
> DataHandler dh = new DataHandler(file);
>
> String request = req.sendOctet(dh);
>
> System.out.println("response " + request);
> } catch (Exception e) {
> // TODO: handle exception
> }
> }
>
> public static Stub proxy(){
> return (Stub) (new Attachment_Impl().getAttachmentPort());
> }
>
> when I run this client i don't receive anything.
>
> I do something wrong in the client in order to transmit an attachment ?
> How can i see if the client send something to the web service ? I try
> with TCP Monitor from Axis Apache but don't capture any SOAP Message
> in this case.
> Any help will be appreciated .
>
> thanks
>
> On 7/18/05, Anne Thomas Manes <atmanes_at_gmail.com> wrote:
> > The service at the endpoint uses the qname of the child element of the
> > SOAP Body to determine how to dispatch the request. That information
> > must be defined as part of the service configuration. Your client must
> > construct an appropriate message (as specified by the WSDL file), and
> > then it should work. The client does not need to indicate the
> > service's method name.
> >
> > On 7/14/05, Oancea Daniel <doancea_at_gmail.com> wrote:
> > > hi everybody,
> > >
> > > a read the Java Web Services Tutorial and I build an JAX-RPC client
> > > which has to interact whit a web service. The problem is that i don't
> > > now exactly how to tell to my client to try to reach a particular
> > > method from the server side. In the tutorial I find that I have to use
> > > <call> method to send a message, which have two arguments: the message
> > > being sent and the destination to which the message should go. Is
> > > nothing about the method that i want to address this message.
> > >
> > > I done something like :
> > >
> > > SOAPMessage response = connection.call(message, endpoint);
> > >
> > > where <endpoint> is the address location of the web service.
> > >
> > >
> > > Thanks
> > >
> > > ---------------------------------------------------------------------
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> > >
> > >
> >
> > ---------------------------------------------------------------------
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> >
> >
>