You need to throw a SOAPFaultException, then you will see the
handleFault being called instead of handleResponse,
Kevin Jones
http://kevinj.develop.com
> -----Original Message-----
> From: Purbhoo, Hansika [mailto:PurbhooH_at_scmb.co.za]
> Sent: 18 December 2003 05:46
> To: users_at_jax-rpc.dev.java.net
> Subject: How does HandleFault get invoked in Handler.
>
>
> Hi
> Does anyone know how to invoke handleFault(MessageContxt ctx)
> method in a Handler class ? The printlns for the other
> methods get printed out, so I know that the Handler class is
> being called and is correctly configured. I have tried
> thowing a JaxRPCException from my method call in the
> Implementation class, but this simply fails.
>
>
> My Handler class is as follows:
> -----------------
> public class ServerHandler extends GenericHandler {
> public ServerHandler() {
> }
>
> public boolean handleResponse(MessageContext context) {
> System.out.println("In the response method:");
> return true;
> }
>
> public void init(HandlerInfo hi) {
> System.out.println("In the init method::");
> }
>
> public boolean handleRequest(MessageContext context) {
> System.out.println("In the Handle request method:");
> return true;
> }
>
> public boolean handleFault(MessageContext context) {
> System.out.println("In the Handle fault method:");
> //Want to do stuff like create a Soap Fault
> return true;
> }
>
>
> public void destroy() { }
>
> public QName[] getHeaders() { return null; }
>
>
> }
> -----------------------
>
> Any Help would be much appreciated
> Thanks
>
>
>
>
>
>
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