Hi Michal,
Will try this and let you know about the reults of the change. Thanks
Michal.
On Mon, Aug 27, 2012 at 3:46 PM, Michal Gajdos <michal.gajdos_at_oracle.com>wrote:
> Hi,
>
> FormDataMultiPart#field you're calling does not set the fileName property
> of the FormDataContentDisposition instance. You can change your client side
> code (creating FormDataMultiPart/FormDataBodyPart objects) to something
> like:
>
> FormDataMultiPart part = new FormDataMultiPart();
> FormDataBodyPart p = new
> FormDataBodyPart(FormDataContentDisposition.name("file").fileName("file").build(),
> finStream, MediaType.TEXT_HTML_TYPE);
> part.bodyPart(p);
>
> and it should work.
>
> Also you may want to change
>
>
> file = new File("xx" + contentDisposition.getFileName());
> new File("xxx").mkdirs();
> file.createNewFile();
>
> to have a correct path to the 'xxx' directory in the first statement: file
> = new File("xxx/" + contentDisposition.getFileName());
>
> regards,
> Michal
>
>
> On 24.8.2012 19:16, selvakumar netaji wrote:
>
> Hi,
>
> Even after changing the url its not working. I just want to know to write
> clients for multipart rest services.
>
> On Thu, Aug 23, 2012 at 10:20 PM, Marek Potociar <
> marek.potociar_at_oracle.com> wrote:
>
>> From what I see the @Path value on your resource does not match the URI
>> in your client. Might that be the cause of your issue?
>>
>> Marek
>>
>> On Aug 23, 2012, at 7:06 AM, selvakumar netaji <vvekselva.gm_at_gmail.com>
>> wrote:
>>
>> Hi,
>>
>>
>> I've created a new multipart part rest service and its working fine with
>> the html form. The rest service is
>>
>> @POST
>> @Path("/Upload")
>> @Produces(MediaType.TEXT_HTML)
>> @Consumes(MediaType.MULTIPART_FORM_DATA)
>> public String uploadFile(@FormDataParam("file") InputStream
>> inputStream,
>> @FormDataParam("file") FormDataContentDisposition
>> contentDisposition) {
>>
>> System.out.println("Method Entry");
>> System.out.println(contentDisposition.getFileName());
>>
>>
>> String result = "not Success";
>> File file = null;
>> if (contentDisposition != null
>> && contentDisposition.getFileName() != null
>> && contentDisposition.getFileName().trim().length() > 0) {
>> try {
>> file = new File("xx"
>> + contentDisposition.getFileName());
>> new File("xxx").mkdirs();
>> file.createNewFile();
>> OutputStream outputStream = new FileOutputStream(file);
>> int read = 0;
>> byte[] bytes = new byte[1024];
>>
>> while ((read = inputStream.read(bytes)) != -1) {
>> outputStream.write(bytes, 0, read);
>> }
>> outputStream.flush();
>> outputStream.close();
>> result = "success";
>>
>> } catch (Exception e) {
>> System.out.println(e.toString());
>> }
>> }
>> System.out.println("Method Exit");
>> return result;
>>
>> }
>>
>> but the form the client code I'm not able to access the client
>>
>>
>> FileInputStream finStream = new FileInputStream(new File(
>> Error.txt"));
>>
>> FormDataMultiPart part = new FormDataMultiPart().field("file",
>> finStream, MediaType.TEXT_HTML_TYPE);
>>
>> WebResource resource = Client.create().resource(
>> "http://localhost:8080/Multipart/Upload<http://localhost:8080/Multipart/rest>
>> ");
>> String response =
>> resource.type(MediaType.MULTIPART_FORM_DATA_TYPE)
>> .post(String.class, part);
>> System.out.println(response);
>>
>>
>>
>> Did I've made any mistakes.
>>
>>
>>
>