Hello,
Try something like this:
Client c = Client.create();
WebResource r = c.resource(“
http://youripaddress:8080/xyz”);
And do whatever you want with resource.
Regards,
Petr
2011/2/11 Christopher Piggott <cpiggott_at_gmail.com>:
> Hi,
>
> I am still trying to figure out how I can create a jersey client and
> have it bound to a specific outbound network interface (identified by
> source IP).
>
> I'm looking at jersey-apache-client as a possible way to do this but I
> still haven't figured out how. Something somewhere creates a
> SocketFactory and calls it. The default way to do this with apache
> http client seems to be:
>
> connectSocket(Socket socket, InetSocketAddress remoteAddress,
> InetSocketAddress localAddress, org.apache.http.params.HttpParams
> params)
>
>
>
> but I don't know how localAddress gets set (this is what I want to override).
>
> My next step, I think, is going to be to try to create my own
> SocketFactory and attach it to jersey-apache-client, but implement the
> SocketFactory to ignore the localAddress and bind whatever I want.
> This is not desirable to me though, since I really need to be able to
> send requests out multiple interfaces.
>
> To explain ... one interface is a cell card, the other is wifi. The
> cell card is expensive. The strategy is to only send certain data via
> wifi, unless the application determined (based on priority, history,
> etc.) that this is important enough to go out the cell card.
>
> Ideally I'd like to make that decision every time I create a jersey Client.
>