Hi Paul,
Thanks for your fast response.
I read the jersey start and did not find some imformation about
jersey-client-components configuration.Maybe I missed some details about
that.
And which format should the file "jersey-client-components" be?XML or .mf?
Or you can give me a example about that.
Thanks in advance.
Best Regards,
Michael
Paul Sandoz wrote:
>
> Hi,
>
> What version of Jersey are you using?
>
> Do you see output like:
>
> INFO: Adding the following classes declared in
> META-INF/services/jersey-client-components to the client configuration:
> class com.sun.jersey.multipart.impl.MultiPartConfigProvider
> class com.sun.jersey.multipart.impl.MultiPartReader
> class com.sun.jersey.multipart.impl.MultiPartWriter
>
> in the logs?
>
> The behavior that you observe indicates that multipart MIME parsing
> has not occurred and instead you are getting complete message (as you
> indicate).
>
> Note that the name "file" in @FormDataParam("file") is incorrect, you
> need to use the same value as that in the name attribute on the form
> input element, in this case "picture". However, i do not think that
> will solve your problem.
>
> Paul.
>
> On Dec 3, 2009, at 3:49 PM, michael_cheng wrote:
>
>>
>> Hi,
>> It's about file upload when my project using jax-rs.I followed the
>> code
>> which the @FormDataParam API mentioned.
>> Please help me about this issue.
>>
>> My client code:
>> <form action="http://localhost:8080/testImage" method="post"
>> enctype="multipart/form-data">
>> <input type="file" name="picture" />
>> <input type="submit" value="Send" />
>> </form>
>>
>> My server code:
>> @POST
>> @Path("testImage")
>> @Consumes(MediaType.MULTIPART_FORM_DATA)
>> public void getImage(
>> @FormDataParam("file") InputStream in) throws IOException{
>> OutputStream os = new FileOutputStream(new
>> File("D:\\good.jpg"));
>> byte[] b = new byte[in.available()];
>> int i = 0;
>> while ((i = in.read(b)) >0) {
>> os.write(b, 0, i);
>> }
>> os.flush();
>> os.close();
>> in.close();
>> }
>>
>> When i upload a picture,the file "D:\\good.png" will show,and the
>> fileSize
>> is as the same .But I can not see the image when I open it.
>> When debuging the program,I noticed that the InputStream contains
>> both the
>> file itself and the file description.Just
>> like"----------789652236442--Content Type=jpg/
>> image........xxxxxxxxxxxx(file
>> itself)----78965222--".
>> And my question is how can I just get the file itself in InputStream?
>> Or I
>> missed something?
>> I will so appreciated if getting your help.Thanks.
>> --
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>>
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>
>
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