Hi,
Is there an exception free way to use WebResource?
I'm asking because I think that having to catch an exception to check
for a 404 when fetching an entity is too verbose.
It would be nice to either have a version of WebResource where it would
be possible to check return codes or where exceptions are thrown for
exceptional things like 500 codes.
Something like:
ret = webresource.path("/").get(SomeEntitiy.class);
if (ret == null) // resource returned 404
doSomething();
else
doSomethingElse();
Also, when doing a create, how do I get the location uri of the new object?
SourceView sv2 =
webResource.path("source").accept("application/xml").put(SourceView.class,
sv);
Ok, I now got the object, but I do not know the URI of the object.
One option would be to have the methods be able to return a response object:
Response r =
webResource.path("source").accept("application/xml").put(SourceView.class,
sv);
if (r.getStatus() == 204) {
...
}
This is a very typical REST client problem I think.
A HTTP response often contains more than just the entity you requested -
how this information should be delivered to the client in a clear way is
not always clear.
Any ideas?
Regards,
Tarjei
--
Tarjei Huse
Mobil: 920 63 413