Laun,
Does JAXB 2.0 use SAX parser by default? How do i make it to use DOM parser?
Could you please provide a sample code snippet. Sorry if i am asking a silly
question. Please care to reply.
Thanks,
Unmarshalling with a SAX parser won't produce DOM nodes, which would be
returned
by Locator.getNode(). You might try to create a DOM tree from the XML file
and
unmarshal from that.
It's strange that you might be able to "perform some business logic" on a
broken
XML document (except diagnose the error, of course).
-W
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