Kevin,
thank you for that idea, I didn't know that it's so easy to get a DOM Node from a JAXB Element.
But I wonder whether XPath is needed for that. Can't I just do that instead:
Node xmlNode = Binder.getXmlNode([JAXBObjectToFindParentOf]);
Node parentNode = xmlNode.getParentNode();
return Binder.getJAXNode(parentNode);
Thanks
Markus
-----Original Message-----
From: Kevin Wooten [mailto:kevin_at_wooten.com]
Sent: Mittwoch, 2. Juli 2008 18:05
To: users_at_jaxb.dev.java.net
Subject: Re: How to get link to Parent Element?
I use XPath to solve this. Which works well since it allows you to
satisfy almost any query you could possibly have. It does require you
to go back and forth between the DOM and the JAXB objects but that is
trivial when using the Binder.
A little psuedo code for your situation..
Node xmlNode = Binder.getXmlNode([JAXBObjectToFindParentOf]);
XPathFactory fac = XPathFactory.newInstance();
XPath xpath = fac.newXPath();
//Set properties on xpath like namespaces used, etc.
Node parentNode = (Node)xpath.evaluate("..", xmlNode,
XPathConstants.NODE);
return Binder.getJAXBNode(parentNode);
Hope this helps!
On Jul 2, 2008, at 8:41 AM, Markus Karg wrote:
> I am a beginner with JAXB and not using schemas at all, only using
> manually annotated classes.
>
> There is the following XML:
>
> <A>
> <B />
> <C />
> </A>
>
> So I wrote classes A, B and C and added @XmlRootElement to both.
>
> But now I want to be able inside of classes B and C to ask for the
> surrounding A.
>
> Is there some "JAXB Magic" that will provide a "Parent Pointer"
> automatically?
> Or what is the best idea to get that pointer (without changing the
> above XML schema)?
>
> Maybe the question is silly, but see, I am a total JAXB beginner. ;-)
>
> Thanks a lot!
> Markus
>
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