users@jaxb.java.net

Re: Creating copy of JAXB Java object content tree?

From: Robert Lowe <rmlowe_at_rmlowe.com>
Date: Fri, 16 May 2003 01:23:35 +0800

You could use the RI extension to generate Serializable classes, as
described here:

http://java.sun.com/webservices/docs/1.1/jaxb-1.0/vendor.html

You could then serialize your content objects to a memory buffer, and then
deserialize from the same buffer. This effectively creates a deep copy.

- Rob


----- Original Message -----
From: "Ganga Sah" <ganga_sah_at_yahoo.com>
To: <JAXB-INTEREST_at_JAVA.SUN.COM>
Sent: Thursday, May 15, 2003 11:50 PM
Subject: Creating copy of JAXB Java object content tree?


> I have a XML instance de-serialized as Java
> Object(content tree) and I want to create another
> copy(clone) of this object. I am finding it hard to do
> so in a generic way "without" traversing the content
> tree and copying each object in turn into a empty
> instance of the object type using create<ObjectType>
> method of JAXB generated ObjectFactory?
> Can any one suggest an easy way to create duplicate
> copy of content tree object?
>
> thanks,
> ganga
>
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