Fw: For a clarification in JAXRPC webservice

From: santhakumar <>
Date: Thu, 7 Apr 2005 10:20:38 +0530

----- Original Message -----
From: santhakumar
To: ; ; ;
Sent: Wednesday, April 06, 2005 5:52 PM
Subject: For a clarification in JAXRPC webservice


This is Santhakumar.

I have develped and deployed a JAXRPC webservice in Tomcat5.0 with JWSDP1.5.

WSDL is created and it works fine for normal java remote methods.

But when I write a code for to connect a live server ( EPP-Extensible Provisioning Protocol TCP server ), I could not invoke the service.

I get the following error:


C:\examples\jaxrpc\dynamicproxy>ant run
Buildfile: build.xml

[java] UrlString = http://localhost:8080/domain-jaxrpc/domain?WSDL
[java] java.rmi.ServerException: JAXRPCSERVLET28: Missing port information
[java] at com.sun.xml.rpc.client.StreamingSender._raiseFault(StreamingS
[java] at com.sun.xml.rpc.client.StreamingSender._send(StreamingSender.
[java] at com.sun.xml.rpc.client.dii.CallInvokerImpl.doInvoke(CallInvok
[java] at com.sun.xml.rpc.client.dii.BasicCall.invoke(
[java] at com.sun.xml.rpc.client.dii.CallInvocationHandler.doCall(CallI
[java] at com.sun.xml.rpc.client.dii.CallInvocationHandler.invoke(CallI
[java] at $Proxy0.domainCheck(Unknown Source)
[java] at dynamicproxy.DomainClient.main(Unknown Source)


Total time: 3 seconds

I tried in many ways to resolve it.But still I could not find out any solutions.

Is there any security settings to be handled for that?

The method works fine and the server is connected when I execute it from the normal java class in command prompt.

But when implementing that method in JAXRPC webservice only I found this problem.

Please share ur ideas with me to resolve this problem.I am at urgent.

Thanks in advance.


The sample example site used is: