Hi Doug,
When I do:
for (Iterator it = messageContext.getPropertyNames(); it.hasNext();) {
Object obj = it.next();
String name = obj.toString();
System.out.println(name);
}
I get:
com.sun.xml.rpc.server.http.HttpServletRequest
com.sun.xml.rpc.server.http.ServletContext
com.sun.xml.rpc.server.http.Implementor
com.sun.xml.rpc.server.http.HttpServletResponse
-----Original Message-----
From: Doug Kohlert [mailto:Doug.Kohlert_at_Sun.COM]
Sent: Monday, 07 March 2005 14:50
To: users_at_jax-rpc.dev.java.net
Subject: Re: HttpServletRequest error???
Brad,
Are you sure that the class name:
com.sun.xml.rpc.server.http.HttpServletRequest is correct?
I can't even find that class in JWSDP 1.5.
Baker, Brad (Contr) wrote:
>
>
>
>
>
------------------------------------------------------------------------
>
> From: Baker, Brad (Contr)
> Sent: Monday, 07 March 2005 12:45
> To: 'users_at_jwsdp.dev.java.net'
> Subject: HttpServletRequest
>
>
>
> Hi all,
>
>
>
> I am creating a Web Service with JWSDP 1.5 and I am trying to get to
> the HttpServletRequest object.
>
>
>
> This is what I have:
>
> messageContext = servletEndpointContext.getMessageContext();
>
> for(java.util.Iterator it = messageContext.getPropertyNames();
> it.hasNext();) {
>
> Object obj = it.next();
>
> String name = obj.toString();
>
> try {
>
> if (name.indexOf("HttpServletRequest") != -1) {
>
> request = (HttpServletRequest) obj;
>
> }
>
> } catch (ClassCastException ex) {
>
> // I get the Exception
>
> }
>
>
>
> When I look at the object name I get:
>
> com.sun.xml.rpc.server.http.HttpServletRequest
>
>
>
> And I am trying to cast it to a:
>
> javax.servlet.http.HttpServletRequest
>
>
>
> Why? Well I am trying to do this generically so if we ever change
> containers we are not hard coded to a specific implementation. It
> seems like this would work if javax.servlet.http.HttpServletRequest is
> implemented.
>
>
>
> Where is the documentation on
> com.sun.xml.rpc.server.http.HttpServletRequest?
>
>
>
> Let me know if anyone has a solution!
>
>
>
> Thanks,
>
> Brad
>
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